You can use a format specification as well, if you want to have minimum width with preceding zeros: > format(int('010101', 2), 'b'.Watch Now This tutorial has a related video course created by the Real Python team. You can pass an integer to bin to see the string representation of a binary literal: > bin(21)Īnd you can combine bin and int to go back and forth: > bin(int('010101', 2)) If you pass it 0 as the base, it will assume base 10 if the string doesn't specify with a prefix: > int('10101', 0)Ĭonverting from int back to human readable binary: You can optionally have the 0b or 0B prefix: > int('0b0010101010', 2)

You can have the zeros and ones in a string object which can be manipulated (although you should probably just do bitwise operations on the integer in most cases) - just pass int the string of zeros and ones and the base you are converting from (2): > int('010101', 2) This is for disambiguation with C-style octal literals, which Python Note that leading zeros in a non-zero decimal number are not allowed.

There is no limit for the length of integer literals apart from what

Integer literals are described by the following lexical definitions: integer ::= decinteger | bininteger | octinteger | hexintegerĭecinteger ::= nonzerodigit ( digit)* | '0'+ ( '0')*īininteger ::= '0' ('b' | 'B') ( bindigit)+ You can express integer literals with a binary format with a 0 followed by a B or b followed by a series of zeros and ones, for example: > 0b0010101010įrom the Python 3 docs, these are the ways of providing integer literals in Python: They're not 'binary' literals, but rather, 'integer literals'. How do you express binary literals in Python?

Python binary to int